How to sum the array of object values and assigned them to the relevant key name

solved using reduce and forEach

Inside the reduce function I'm running a forEach on the array of keys of the incomes object/attribute. For each key which is a date I'm checking if the accumulator of the reduce function contains an attribute for each date and creates if not. After creating the attribute I'm summing the value for the current date attribute.

const data = [
  {
    group: 'A',
    incomes: {
      "2019-12": 100,
      "2020-12": 200,
      "2021-12": 15
    }
  },
  {
    group: 'B',
    incomes: {
      "2019-12": 25,
      "2020-12": 50,
    }
  }
]

const totalIncomes = data.reduce((acc,curr)=> {
    Object.keys(curr.incomes).forEach((key, index) => {
   if(!acc[key]){
        acc[key] = 0;
   }
   acc[key]+=curr.incomes[key]
  });
   return acc;
},{})

console.log(totalIncomes)

Maybe this is not the pretties solutions but you can do it like this, the function is of course not necessary.

const data = [
  {
    group: "A",
    incomes: {
      "2019-12": 100,
      "2020-12": 200,
      "2021-12": 15,
    },
  },
  {
    group: "B",
    incomes: {
      "2019-12": 25,
      "2020-12": 50,
    },
  },
];

getterInformation(data);

function getterInformation(object) {
  let objectWithCalculatedValues = {};

  object.forEach((items) => {
    for (const key in items.incomes) {
      if (objectWithCalculatedValues[key] === undefined) {
        objectWithCalculatedValues[key] = 0;
      }

      objectWithCalculatedValues[key] += items.incomes[key];
    }
  });

  console.log(objectWithCalculatedValues);
}

Assuming that this information may be useful to readers who may be unable to obtain necessary guidance (due to various possible reasons), here is one possible way to achieve the objective (solution):

const aggregateIncomesByMonth = () => (
  data.map(d => Object.entries(d.incomes).map(([k, v]) => ({
    key: k,
    value: v
  }))).flat().reduce((fin, itm) => ({
    ...fin,
    [itm.key]: (fin[itm.key] || 0) + itm.value
  }), {})
);

Explanation

1. Extract only the incomes from the data array
2. For each income object, get the key-value pair and transform into another object of the structure {key: 20yy-mm, value: nn}
3. Use .flat() to transform the result from step-2 into a 1-dimensional array
4. Use .reduce to sum the value for those cases where the key (ie, 20yy-mm) matches.

Code-snippet

const data = [{
    group: 'A',
    incomes: {
      "2019-12": 100,
      "2020-12": 200,
      "2021-12": 15
    }
  },
  {
    group: 'B',
    incomes: {
      "2019-12": 25,
      "2020-12": 50,
    }
  }
];

const aggregateIncomesByMonth = () => (
  data.map(d => Object.entries(d.incomes).map(([k, v]) => ({
    key: k,
    value: v
  }))).flat().reduce((fin, itm) => ({
    ...fin,
    [itm.key]: (fin[itm.key] || 0) + itm.value
  }), {})
);

console.log(aggregateIncomesByMonth());

My approach here is to destructure the array. This way I have all the data of the incomes of group A in the variable A and the same for B.

Then I do a double loop to compare both objects data and see if the dates match. If so, sum the incomes and add the data to the total object.

const data = [
  {
    group: 'A',
    incomes: { "2019-12": 100, "2020-12": 200, "2021-12": 15 }
  },
  {
    group: 'B',
    incomes: { "2019-12": 25, "2020-12": 50 }
  }
]

let A, B, total = {};

[A, B] = [data[0].incomes, data[1].incomes]

for(const date in A){
  for(const d in B){
   total[date] = date === d ? A[date] + B[date] : A[date]
  }  
}

console.log(total)