Choosing random value from weighted options in java

user_16818831 0
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When the user clicks, a random output from a set of outputs must be selected. The chances for one value needs to be higher than the other. For example, you click a button and you either receive Bronze, Silver, Gold, or Platinum. Obviously, if you click randomly, you should receive Bronze more than Silver, more than Gold, more than Platinum. For example, could it maybe look like this:

printRandom("Bronze", 30, "Silver", 20, "Gold", 10, "Platinum", 5, "You didn't get anything.");

Where the final result is when you were unlucky enough to get none. I've been having trouble with making one option more common than the other, not choosing a value in the first place. Thank you.

random java
1 Answers

If you want to keep it simple, you could do the following:

int random = Math.random();

if (random < 0.05) { // 5/100
  return "Platinum";
} else if (random < 0.1) { // 10/100
  return "Gold";
} else if (random < 0.2) { // 20/100
  return "Silver";
} else if (random < 0.3) { // 30/100
  return "Bronze";
} else {
  return "You didn't get anything.";
}
user_24723980
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