Convert XML to JSON which should support if the xml tag has attributes in go programming?

I want to create JSON from XML vice versa, so I got stuck at the point if XML contains the attributes e.g. <name id = "12"> Stack <name> so if this type of XML came how can I solve it.

I have searched on the internet I got this code from this site but it doesn't fill my requirement

package main

import (
    "encoding/json"
    "encoding/xml"
    "fmt"
)

type DataFormat struct {
    ProductList []struct {
        Sku      string `xml:"sku" json:"sku"`
        Quantity int    `xml:"quantity" json:"quantity"`
    } `xml:"Product" json:"products"`
}

func main() {
    xmlData := []byte(`<?xml version="1.0" encoding="UTF-8" ?>
<ProductList>
    <Product>
        <sku >ABC123</sku>
        <quantity>2</quantity>
    </Product>
    <Product>
        <sku>ABC123</sku>
        <quantity>2</quantity>
    </Product>
</ProductList>`)

    data := &DataFormat{}
    err := xml.Unmarshal(xmlData, data)
    if nil != err {
        fmt.Println("Error unmarshalling from XML", err)
        return
    }

    result, err := json.Marshal(data)
    if nil != err {
        fmt.Println("Error marshalling to JSON", err)
        return
    }

    fmt.Printf("%s\n", result)
}

this solution is working on a given sample XML but failed if the XML tag has attributes.

what do I need to modify in this code so that it works for XML which has attributes?

Edit solution:

From the comment i got to know that i need to add atrr and omitempty option then it will work and for marking of attributes i can use @ or $

sample code modification would be for my question:

type DataFormat struct {
    ProductList []struct {
        Id       string `xml:"id,attr,omitempty" json:"@id,omitempty"`
        Sku      string `xml:"sku" json:"sku"`
        Quantity int    `xml:"quantity" json:"quantity"`
    } `xml:"Product" json:"products"`
}

Thanks for the explanation.