Get the Second Highest Date in JavaScript/ES6

Question

I have a problem getting the second highest date in ES6. I'm using moment.js too. Its supposed to be getting the id of 3.

const datas = [
    {
        id: 1,
        date: moment(String('Apple & Banana - 20072021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
    },
    {
        id: 2,
        date: moment(String('Apple & Oranges - 30082021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
    },
    {
        id: 3,
        date: moment(String('Lemon & Oranges - 30102021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
    },
    {
        id: 4,
        date: moment(String('Honeydew - 30112021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
    }
];

const secondLatestDate = new Date(datas.map(file => new Date(file.date)).sort().reverse()[1]);

const finalResult = datas.find(file => file.date.getTime() === secondLatestDate.getTime());

console.log(finalResult)

user_9153448 · Answer

You should use custom sort function as:

datas.sort((a, b) => a.date - b.date)

There is no need to use find when you are reverseing the array and getting the index 1 from it.

Note: I deliberately change the order of the datas array

const datas = [{
    id: 1,
    date: moment(String('Apple & Banana - 20072021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
  },
  {
    id: 2,
    date: moment(String('Apple & Oranges - 30082021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
  },
  {
    id: 4,
    date: moment(String('Honeydew - 30112021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
  },
  {
    id: 3,
    date: moment(String('Lemon & Oranges - 30102021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
  }
];

const secondLatestDate = datas.sort((a, b) => a.date - b.date).reverse()[1];
console.log(secondLatestDate);

or you can directly find the second largest after sort. There is no need to reverse the array

datas.sort((a, b) => a.date - b.date)[datas.length - 2]

const datas = [{
    id: 1,
    date: moment(
      String('Apple & Banana - 20072021').match(/[0-9]/g).join(''),
      'DDMMYYYY'
    ).toDate(),
  },
  {
    id: 2,
    date: moment(
      String('Apple & Oranges - 30082021').match(/[0-9]/g).join(''),
      'DDMMYYYY'
    ).toDate(),
  },
  {
    id: 4,
    date: moment(
      String('Honeydew - 30112021').match(/[0-9]/g).join(''),
      'DDMMYYYY'
    ).toDate(),
  },
  {
    id: 3,
    date: moment(
      String('Lemon & Oranges - 30102021').match(/[0-9]/g).join(''),
      'DDMMYYYY'
    ).toDate(),
  },
];

const secondLatestDate = datas.sort((a, b) => a.date - b.date)[datas.length - 2];
console.log(secondLatestDate);

user_5487267 · Answer

If you're at all concerned with time complexity you could do this in one 'n' by implementing a function that keeps track of both the highest and second highest values. Maybe something like this:


const datas = [{
    id: 1,
    date: moment(String('Apple & Banana - 20072021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
  },
  {
    id: 2,
    date: moment(String('Apple & Oranges - 30082021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
  },
  {
    id: 4,
    date: moment(String('Honeydew - 30112021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
  },
  {
    id: 3,
    date: moment(String('Lemon & Oranges - 30102021').match(/[0-9]/g).join(""), 'DDMMYYYY').toDate()
  }
]


function getSecondHighest(dates){
    let highest = 0;
    let secondHighest = 0;

    for(const val of dates){
        const currentDate = val.date
        if(currentDate > highest){
            secondHighest = highest;
            highest = currentDate;
        } else if(currentDate > secondHighest){
            secondHighest = currentDate
        } else {
            continue;
        }
    }

    return secondHighest;
}

Get the Second Highest Date in JavaScript/ES6

2 Answers