Golang - split string into at most N parts?

user_1568658 0
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Code & problem

// parse request,
parts := strings.Split(message, ",")
uuid := parts[0]
data := parts[1]

The above code split message by ,, I actually want 2 parts.
But the data part itself may contain ,, so it may be split into more than 2 parts.

e.g

I want to split string:
"19177360-2765-4597-a58e-519783a0d51d,a,b,c"
into:
["19177360-2765-4597-a58e-519783a0d51d", "a,b,c"]
not:
["19177360-2765-4597-a58e-519783a0d51d", "a", "b", "c"]

Possible solution

With strings.Split(message, ","), it split into 4 parts.
I can search for first ,, then get substrings by hand.

Question

But is there a convenient function to specify the max N parts to split the string into.

Java has such built-in methods for String, is there similar Go libraries for string ?

Thanks.

go split string
1 Answers

strings.SplitN is the function that you wants, the third parameter is the number of parts that you want to split:

arrayString := strings.SplitN(message, ",", 2)
// arrayString[0] = 19177360-2765-4597-a58e-519783a0d51d
// arrayString[1] = a,b,c
user_34159840
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