I need to find null applicant_id by web_user_id after the min(date) where applicant_id was first filled
For example, for web_user_id 23 we will find null applicant_id after the row_id = 3, because it is first filled applicant_id with min(date)
For web_user_id 90 we will find null applicant_id after row_id = 11, because it is first filled applicant_id with min(date)
the table is:
| row_id | applicant_id | web_user_id | date |
| ------- | ------------- | ------------- | ---- |
| 1 | null | 23 | 2020 |
| 2 | null | 23 | 2021 |
| 3 | 77 | 23 | 2022 |
| 4 | 77 | 23 | 2023 |
| 5 | 77 | 23 | 2024 |
| 6 | null | 23 | 2025 |
| 7 | 77 | 23 | 2026 |
| 8 | null | 23 | 2027 |
| 9 | 77 | 23 | 2028 |
| 10 | null | 90 | 2020 |
| 11 | 55 | 90 | 2021 |
| 12 | 55 | 90 | 2022 |
| 13 | 55 | 90 | 2023 |
| 14 | 55 | 90 | 2024 |
| 15 | null | 90 | 2025 |
| 16 | 55 | 90 | 2026 |
| 17 | 55 | 90 | 2027 |
the condition is: select min(date), applicant_id, row_id, web_user_id and after this date I need to find rows where applicant_id is null
As a result I would to have this table: https://prnt.sc/264om6u
| row_id | applicant_id | web_user_id | date |
| ------- | ------------- | ------------- | ---- |
| 6 | null | 23 | 2025 |
| 8 | null | 23 | 2027 |
| 15 | null | 90 | 2025 |
SQL for creating the table
create table dbo.tabl (
row_id int,
applicant_id int,
web_user_id int,
"date" int
);
insert into dbo.tabl values
(1, null, 23, 2020),
(2, null, 23, 2021),
(3, 77, 23, 2022),
(4, 77, 23, 2023),
(5, 77, 23, 2024),
(6, null, 23, 2025),
(7, 77, 23, 2026),
(8, null, 23, 2027),
(9, 77, 23, 2028),
(10, null, 90, 2020),
(11, 55, 90, 2021),
(12, 55, 90, 2022),
(13, 55, 90, 2023),
(14, 55, 90, 2024),
(15, null, 90, 2025),
(16, 55, 90, 2026),
(17, 55, 90, 2027);