JAX: Converting Concrete Tracer values to regular float values doesnt work

I am using JAX for auto differentiation. In this, I am trying to convert concrete tracer values to regular float values using astype(float) but it still seems to return a concrete tracer value. However when I do astype(int) it seems to correctly convert the concrete tracer into an int.

Here is an example:

import jax
from jax import numpy as jnp

def func(mu):

  print((mu.astype(float)))
  print(mu)
  print(mu.astype(int))

  return mu

f = jax.grad(func)

print(f(jnp.array(5.0)))

This returns the following:

Traced<ConcreteArray(5.0)>with<JVPTrace(level=2/0)>
  with primal = Traced<ConcreteArray(5.0):JaxprTrace(level=1/0)>
       tangent = Traced<ShapedArray(float32[]):JaxprTrace(level=1/0)>
Traced<ConcreteArray(5.0)>with<JVPTrace(level=2/0)>
  with primal = Traced<ConcreteArray(5.0):JaxprTrace(level=1/0)>
       tangent = Traced<ShapedArray(float32[]):JaxprTrace(level=1/0)>
5
1.0

Clearly print(mu) and print(mu.astype(float)) seem to return the exact same thing while print(mu.astype(int)) returns the correct int value. Is this expected? This is a simple example but in my original function I would like to convert one of the input parameters into a regular float value.

Thanks in advance!