I want to open Amazon App when someone press the elevated button. I am using url_launcher package and using affiliate product link.
ElevatedButton(
onPressed: () {
launch("https://www.amazon.com/");
},
child: Text("amazon"),
),
Try below code hope its helpful to you.
You must use url_launcher package from here add this dependency in your pubspec.yaml file
You can refer my answer here also for open app from URL
create one widget
InkWell(
hoverColor: Colors.transparent,
child: Image.network(
'https://upload.wikimedia.org/wikipedia/commons/d/de/Amazon_icon.png',
width: 70,
height: 70,
),
onTap: () => amazon(),
)
Create ontap function
amazon() async {
const url =
'https://www.amazon.com/';// or add your URL here
if (await canLaunch(url)) {
await launch(url);
} else {
throw 'Could not launch $url';
}
}