I am executing the below code:
s = 'python'
a, b, *c, d = s[0], s[1], s[2:-1], s[-1]
print(c)
I am getting output as ['tho']
Please help me understand why the output is not ['t', 'h', 'o'] ?
As we are using the * operator on LHS, so the output should be ['t', 'h', 'o'] and not ['tho']
You would need to unpack the string as well, else there is only a single element ('tho'):
s = 'python'
a, b, *c, d = s[0], s[1], *s[2:-1], s[-1]
print(c)
Output: ['t', 'h', 'o']
I this what you were looking for is:
a,b,*c,d = s
print(c)
where unpacking really makes sense
It's because s[2:-1] is not unpacked. There is no reason for it to unpack.
You need:
a, b, *c, d = s[0], s[1], *s[2:-1], s[-1]
Unpack assignments will only unpack into one sequence of multiple values when there are multiple non-attached values, like 't', 'h', 'o', not when the value is 'tho'.
Now:
print(c)
Is:
['t', 'h', 'o']