moving characters by using regex

user_14875584 0
Viewed 61

I'm trying to move matched characters to the end of sentence.

from

300p apple in house
orange 200p in school

to

apple in house 300p
orange in school 200p

So I matched (.+)([\d]+p)(.+)$ and substituted with \1 \3 \2. But the result is like

30  apple in house 0p
orange 20  in school 0p

I also checked greedy concept, but I don't know what is problem. How can I fix this?

regex
2 Answers

You can use

^(.*?)(\d+p) *(.+)

Replace with \1\3 \2.

See the regex demo. Details:

  • ^ - start of string (or line if you use a multiline mode)
  • (.*?) - Group 1: any zero or more chars other than line break chars as few as possible
  • (\d+p) - Group 2: one or more digits, and then a p char
  • * - zero or more spaces
  • (.+) - Group 3: any one or more chars other than line break chars as many as possible (since it is a greedy subpattern, no $ anchor is required, the match will go up to the end of string (or line if you use a multiline mode)).
user_38329700

With your shown samples only, please try following regex.

^(\D+)?(\d+p)\s*(.+)$

Online demo for above regex

Explanation:

^(\D+)?  ##Matching from starting and creating 1st capturing group which has all non-digits in it and keeping it as optional.
(\d+p)   ##Creating 2nd capturing group which matches 1 or more digits followed by p here.
\s*      ##Matching 0 or more occurrences of spaces here.
(.+)$    ##Creating 3rd capturing group here which has everything in it.
user_58665800
Related