In this code:
t = {
num = '',
}
t[0].num = '0'
t[1].num = '1'
t[2].num = '2'
Is there a way for me to delete t[0], then shift all of the table's values down, so that afterword it looks like this:
t[0].num = '1'
t[1].num = '2'
Example with imaginary functions:
t = {
num = '',
}
t[0].num = '0'
t[1].num = '1'
t[2].num = '2'
for i=0,tableLength(t) do
print(t[i])
end
--Output: 012
remove(t[0])
for i=0,tableLength(t) do
print(t[i])
end
--Output: 12
t = {
num = '',
}
t[0].num = '0'
t[1].num = '1'
t[2].num = '2'
This code will cause errors for indexing t[0], a nil value.
t only has one field and that is t.num
You need to do something like this:
t = {}
for i = 0, 2 do
t[i] = {num = tostring(i)}
end
if you want to create the desired demo table.
As there are many useful functions in Lua that assume 1-based indexing you I'd recommend starting at index 1.
local t = {1,2,3,4,5}
Option 1:
table.remove(t, 1)
Option 2:
t = {table.unpack(t, 2, #t)}
Option 3:
t = table.move(t, 2, #t, 1, t)
t[#t] = nil
Option 4:
for i = 1, #t-1 do
t[i] = t[i+1]
end
t[#t] = nil
There are more options. I won't list them all. Some do it in place, some result in new table objects.
As stated in this answer, by creating a new table using the result of table.unpack:
t = {table.unpack(t, 1, #t)}