Get as many nested Records in returnType as the arguments passed to the function

user_17378703 0
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What I am trying to achieve is typing a deeply nested ReturnType of a function, based on the number of arguments provided in the "rest" argument. For example, if we have:

getFormattedDates(
  dates: Date[],
  ...rest: string[] // ['AAA', 'BBB', 'CCC', etc...]
): Record<string, Record<string, Record<string,etc...>>>

The last nested object should be of type Record<string, Date[]>, while if there is no 2nd argument, the return type should be Date[].

So far I have tried googling various things, but I couldn't get a hold on such a type, and I would also like to understand the logic behind it.

This is my first question ever asked, so I hope it is explicit enough. :)

Hope someone can shed some light on this issue. Thanks!

nested-object typescript-typings typescript return-type function
1 Answers

You can build the type recursively:

type ToRecord<T> = T extends [string, ...infer Rest]
    ? Record<string, ToRecord<Rest>>
    : Date[]

declare function getFormattedDates<T extends string[]>(
    dates: Date[],
    ...rest: T // ['AAA', 'BBB', 'CCC', etc...]
): ToRecord<T>

const p0 = getFormattedDates([]) // Date[]
const p1 = getFormattedDates([], 'AAA') // Record<string, Date[]>
const p3 = getFormattedDates([], 'AAA', 'BBB', 'CCC') // Record<string, Record<string, Record<string, Date[]>>>

Playground

user_11130020
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