How can compare and exclude arrays elements with other arrays elements in react native

Admin 1
Viewed 47

I need to compare two arrays here is one arrays [...showid] here is another arrays [...swipeeachotheruserId]

in this arrays ,some id will contains this ids will same but not all are same [ 3, 5 , 7 , 10 ,14 ] [ 2, 5, 7, 1, 20, 14 ]

some elements will be same but not all elements same

logic is

showid===swipeeachotheruserId ? will exclude not same id and display here : show id

how can compare and exclude this arrays values

react-native javascript
2 Answers

const showid = [ 3, 5, 7 , 10 ,14 ];
const swipeeachotheruserId = [ 2, 5, 7, 1, 20, 14 ];

const duplicates = showid.filter(value => swipeeachotheruserId.some(oneElement => oneElement === value));

const mergedArray = [ 
  ...showid, 
  ...swipeeachotheruserId.filter(value => !duplicates.some(oneDuplicate => oneDuplicate === value))
];

const arrayWithoutDuplicate = mergedArray.filter(oneElem => !duplicates.some(value => oneElem === value));

console.log(duplicates);
console.log(mergedArray);
console.log(arrayWithoutDuplicate);

user_30547220

if you want to pass the objects which are in both arrays, use this:

return showid.filter(e=>sipeeachotheruserid.includes(e))

if you want to pass the objects which are noth in swipeachotheruserid, then use this:

return showid.filter(e=>!swipeeachotheruserid.includes(e))
user_112593040
Related