replace cell in dataframe if it contains a string

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I need to replace every cell in a python dataframe if it contains the string p.

A    B   C 
150  5   5p
10   4   8p
1    20  10

to make it look like

A    B   C 
150  5   None
10   4   None
1    20  10

I tried it with

df.replace(df['C'] == df['C'].str.contains('d'), value =None)

which didnt work, can someone tell me why it didnt?

pandas dataframe python
1 Answers

You could use applymap:

import pandas as pd

df = pd.DataFrame({"A":[150, 10, 1], "B":[5,4,20], "C":["5p", "8p", 10]})

df.applymap(lambda x: float(str(x).replace("p","")))

OUTPUT

       A     B     C
0  150.0   5.0   5.0
1   10.0   4.0   8.0
2    1.0  20.0  10.0

FOLLOW UP

Following the comment by @n1colas.m, this is the approach if you want None instead of a number parsing:

df.applymap(lambda x: None if "p" in str(x) else x)

OUTPUT

     A   B     C
0  150   5   NaN
1   10   4   NaN
2    1  20  10.0

or

df.applymap(lambda x: "None" if "p" in str(x) else x)

OUTPUT

     A   B     C
0  150   5  None
1   10   4  None
2    1  20    10
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