Automatic template deduction C++20 with aggregate type

user_15438837 0
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I am puzzled about this C++ code:

template <class T>
struct Foo {
  T value;
};
 
int main() {
    return Foo<int>(0).value;
    // Below code works as well in gcc
    // return Foo(0).value;
}

It compiles with GCC 10 in C++20 standard (but not in C++17 standard) and latest MSVC, but not with clang 13 or 14, even in C++20.

According to the standard (from cppreference) it should be possible to instantiate Foo at least when specifying the templated type.

Why is this related to C++20 ? I see nothing that change in the template deduction specification (I maybe missed something).

Also (this is strange), GCC in C++20 mode even compiles when we call Foo without specifying templated type (Foo(0)).

godbolt link here

aggregate-type c++20 templates c++
2 Answers

It compiles with GCC 10 in C++20 standard (but not in C++17 standard) and latest MSVC.

This is because GCC 10 and the latest MSVC implement allow initializing aggregates from a parenthesized list of values, which allows us to use parentheses to initialize aggregates.

Also (this is strange), GCC in C++20 mode even compiles when we call Foo without specifying templated type (Foo(0)).

This is because GCC 10 implements class template argument deduction for aggregates, which makes T automatically deduced to int.

Please note that clang does not currently implement these two C++20 features, so your code cannot be accepted by clang.

You can refer to cppreference to get the current compiler's support for C++20 features.

user_116387180

Regarding your link, the compiler will tell you what's wrong with your call:

error: no matching function for call to 'Foo::Foo(int)'

So, the problem is that you try to call a non-existing constructor. Your class Foo has the default constructor Foo() only.

Just change return Foo<int>(0).value; to return Foo<int>().value; and it would work. Otherwise you would need a constructor like Foo(T) {}.

user_15317650
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