I am new to c++, so please do not judge me strictly. I am trying to get size of array, but this code sample always returns 2. Also I can use only C++11. What is the problem and how can I deal with it? Thank you in advance.
String string = "paris";
char * array = new char [string.length() + 1];
int arraySize = sizeof(array) / sizeof(array[0]);
It returns 2 because array is a pointer , meaning sizeof(array) returns the size of the pointer, not the array. You have 16-bit pointers?
sizeof(array) / sizeof(array[0]); only works for compile-time arrays.
Solution is to use std::vector or std::array.
Also use std::size_t for lengths, not int.
You can't find out the size of an array that was created using the keyword new(the way you did). The size of an array allocated using new[] is not stored in any way in which it can be accessed later.
You should instead use std::vector which stores the length for you.
std::string string = "paris";
std::vector<char> myVec(string.length() + 1); //creates vector of size string.length() + 1
int arraySize = myVec.size();