Clone search fields in jquery/ajax

user_17554446 0
Viewed 64

I'm new to this forum and I would like to tell you my problem already.

I need a multiple search field, when I go to enter the first letters I get the results through an AJAX call made on a file in php, the problem is that in the second input field that I have cloned the AJAX scan does not work and I do not suggestions come out. So how can I go about making multiple search fields work?

I am attaching the code to make you understand better. Thank you all.

<div class="cont">
      <input type="text" class="form-control search" id="search">
      <button id="add" onClick="add()">+</button>
  </div>
    
<table class="table table-hover">  
  <thead>
    <tr>
      <th>Firstname</th>
      <th>Lastname</th>
      <th>City</th>
      <th>Salary</th>
    </tr>
  </thead>
  <tbody id="output">
    
  </tbody>
</table>



function add(){
    $("#search").clone().val("").attr("id", "search").appendTo(".cont");
}   

$("#search").keyup(function(){
    $.ajax({
        type:'POST',
        url:'search.php',
        data:{
          name:$(this).val(),
        },
        success:function(data){
           $(".#output").html(data);
        return data;
        }
    });
});

I did as you said, but the ajax call in the second input doesn't work, should I call the ajax function to make it work on the new input? How could I do?

Thanks a lot everyone, I solved it

php jquery ajax
1 Answers

You need to be identifying a class search .. You are calling an ID which is supposed to be unique

When cloning remove the ID attribute and use addClass('search')

$("#search").clone().val("").addClass("search").appendTo(".cont");

Then change your selector from: $("#search")

To $(".search")

in effect calling any element with the class search on keyup

UPDATE

as @ADyson mentioned in the comment .. You will need to bind the keyup action .. The easiest way to do this is using on() ( from the deprecated .live() ). IE:

$(document).on('keyup', '.search', function(){

FULL SNIPPET:

function add(){
    $("#search").clone().val("").addClass("search").appendTo(".cont");
}   

$(document).on('keyup', '.search', function(){
    alert('Call AJAX');
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="cont">
      <input type="text" class="form-control search" id="search">
      <button id="add" onClick="add()">+</button>
  </div>
    
<table class="table table-hover">  
  <thead>
    <tr>
      <th>Firstname</th>
      <th>Lastname</th>
      <th>City</th>
      <th>Salary</th>
    </tr>
  </thead>
  <tbody id="output">
    
  </tbody>
</table>

Check out the API Documentation for a full list of events handled through .on()

user_15076910
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