I use ListChangeListener to listen to changes in Tab Pane.
private final TabPane tabBar = new TabPane();
...
tabBar.getTabs().addListener(this::tabsChanged);
I'm trying to listen to tab move events with the following code:
private void tabsChanged(ListChangeListener.Change<? extends Tab> change) {
while (change.next()) {
if (change.wasPermutated()) {
for (int i = change.getFrom(); i < change.getTo(); i++) {
System.out.println(i + " -> " + change.getPermutation(i));
}
}
}
}
As JavaFX documentation says:
In order to get the new position of an element, you must call: change.getPermutation(oldIndex). Returns: the new index of the same element.
But in my case change.getPermutation(i) always returns just i.
For example, I have 4 tabs. Their indexes are: 0, 1, 2, 3.
Then I move the 4th tab to the first position.
I expect the following output:
0 -> 1
1 -> 2
2 -> 3
3 -> 0
But I get:
0 -> 0
1 -> 1
2 -> 2
3 -> 3
How can I make it work as I need?