With this code:
data = pd.DataFrame({'car_plate':['1v','2f','3a','h0','m1'],
'car_brand':['Honda','Honda','Ford','Audi','Audi'],
'last_seen':['01/01/2020','01/02/2020','01/03/2020','01/04/2020','01/05/2020']})
data['last_seen'] = pd.to_datetime(data['last_seen'])
I have the following dataframe:
| car_plate | car_brand | last_seen | |
|---|---|---|---|
| 0 | 1v | Honda | 2020-01-01 00:00:00 |
| 1 | 2f | Honda | 2020-01-02 00:00:00 |
| 2 | 3a | Ford | 2020-01-03 00:00:00 |
| 3 | h0 | Audi | 2020-01-04 00:00:00 |
| 4 | m1 | Audi | 2020-01-05 00:00:00 |
I would like that for ever car_brand, I mark to 1 the row that have the most recent last_seen, so the output is:
| car_plate | car_brand | last_seen | recent | |
|---|---|---|---|---|
| 0 | 1v | Honda | 2020-01-01 00:00:00 | 0 |
| 1 | 2f | Honda | 2020-01-02 00:00:00 | 1 |
| 2 | 3a | Ford | 2020-01-03 00:00:00 | 1 |
| 3 | h0 | Audi | 2020-01-04 00:00:00 | 0 |
| 4 | m1 | Audi | 2020-01-05 00:00:00 | 1 |
As the 2f is the most recent Honda, 3a is the most recent Ford, and the m1 is the most recent Audi.
I've been thinking of this idea, pseudo code: group by car_brand, get max last_seen, get the index of that row, create a column seen and set to 1 those indexes.
P.S.: I'm also wondering how it would work if I add more levels to the combintion, e.g car_owner, and I would like the most recent car_plate + car_owner combination for every car_brand.