Divide by a number only non Nan values in a data frame column

user_14073111 0
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Lets say i have a dataframe that looks like this:

       Col1
0    100,000,000
1    234,343,000
2      NaN
3    213,564,545
4      NaN
5    678,000
6     200

how can divide the non NaN values in Col1 with 1000 and have this desirable output:

        Col1            Col2
0    100,000,000      100,000
1    234,343,000      234,343
2        NaN            NaN
3    213,564,545      213,564
4        NaN            NaN
5      678,000          678
6     200               0.2

I tried to do df['Col1'].div(1000) but it is not working because of the NaN values

pandas dataframe python-3.x python
1 Answers

It looks like you have strings, so dividing by 1000 is just removing the last comma and last 3 digits. You can use a regex:

df['Col2'] = df['Col1'].str.replace(',?\d{,3}$', '', regex=True)

output:

          Col1     Col2
0  100,000,000  100,000
1  234,343,000  234,343
2          NaN      NaN
3  213,564,545  213,564
4          NaN      NaN
5      678,000      678

emulating a true division:

only small numbers as float
df['Col2'] = df['Col1'].str.replace(r'(.*?)(,?(\d{1,3}))$',
                                    lambda m: m.group(1) if m.group(1) else ('0.'+m.group(3).zfill(3)),
                                    regex=True)

output:

          Col1     Col2
0  100,000,000  100,000
1  234,343,000  234,343
2          NaN      NaN
3  213,564,545  213,564
4          NaN      NaN
5      678,000      678
6           23    0.023
all floats
df['Col2'] = df['Col1'].str.replace(r'(.*?)(,?(\d{1,3}))$',
                                    lambda m: (m.group(1) if m.group(1) else '0')+'.'+m.group(3).zfill(3),
                                    regex=True)

output:

          Col1         Col2
0  100,000,000  100,000.000
1  234,343,000  234,343.000
2          NaN          NaN
3  213,564,545  213,564.545
4          NaN          NaN
5      678,000      678.000
6           23        0.023
user_163434640
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