I want to replace back slashes in a string with forward slashes , but the following points needed to be followed while doing this :
If there are 2 or more consecutive back slashes , then all of it should be considered as a single back slash and needed to be converted to a forward slash.
For example:
Input : r'Removing\\\white\\spaces\\from\\a\\list' Output I need : 'Removing/white/spaces/from/a/list'If there is one or more blank or white spaces in between 2 backslash , then the part of the string after the white spaces should be removed from the output. That is only need to replace the back slashes till the white space .
For example:
Input : r'Removing\\white\\ \\spaces\\from\\a\\list' Output : Removing/white
I have tried the following but it don't give the correct output if there are 3 consecutive back slashes and also throws error while I try to delete the white spaces :
def function(String,SeparIn,SeparOut):
TAG = String.split(SeparIn)
for i in range(len(TAG)):
if len(TAG[i])==0:
TAG.remove(TAG[i])
for i in range(len(TAG)):
if TAG[i]==" " :
del TAG[i:len(TAG)]
# initialize an empty string
RESULT =SeparOut
# traverse in the string
RESULT=RESULT.join(TAG) #joining the string elements by the new delimiter
# return string
return RESULT
String=r'Removing\\ \\white\\spaces\\from\\a\\list'
SeparIn=r'\\'
SeparOut='/'
function(String,SeparIn,SeparOut)
The above code prints the following output if there are 3 consecutive back slashes :
input:
String=r'Removing\\\white\\spaces\\from\\a\\list'
SeparIn=r'\\'
SeparOut='/'
function(String,SeparIn,SeparOut)
Output my code prints:
'Removing/\\white/spaces/from/a/list'
The output that I want :
'Removing/white/spaces/from/a/list'
The above code throws the following error if there is white spaces :
IndexError Traceback (most recent call last)
<ipython-input-88-37b8d8f131c7> in <module>()
20 SeparIn=r'\\'
21 SeparOut='/'
---> 22 function(String,SeparIn,SeparOut)
<ipython-input-88-37b8d8f131c7> in function(String, SeparIn, SeparOut)
5 TAG.remove(TAGELEM[i])
6 for i in range(len(TAG)):
----> 7 if TAG[i]==" " :
8 del TAG[i:len(TAG)]
9
IndexError: list index out of range
Please do help if anyone knows a solution for this .Thanks in advance !!