How can I do handle a error in a error handling code?

user_17383815 0
Viewed 21

I am trying to do this code:

try:
    print(int(number1)*int(number2))
except ValueError:
    print(int(number1)*float(number2))
except ValueError:
    print(float(number1)*float(number1))
except ValueError:
   print(float(number1)*int(number1))

But it finds an error before finishing the code. Can anyone help me?

error-handling python
1 Answers

I will assume you need nested try / except:

number1 = '123'
number2 = '456.78'
try:
    print(int(number1)*int(number2))
except ValueError:
    try:
        print(int(number1)*float(number2))
    except ValueError:
        try:
            print(float(number1)*float(number1))
        except ValueError:
            print(float(number1)*int(number1))

Prints:

56183.939999999995
user_150353140
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