return array and convert it to list flutter firebase

user_12813170 0
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Future<bool> checkLiked(String questionID) async {
    DocumentReference ref = questionBank.doc(questionID);
    List<dynamic>? list;
    await ref.get().then((value) {
      list = value['userLiked'];
    });
    print(list!.contains(uid));
    return list!.contains(uid);
  }

it alawys return false also the uid already in the list and when i print the list it empty but inside the then method it contain the uid how to return the list outside the then method

google-cloud-firestore firebase flutter
2 Answers

Maybe you're printing the list outside, but printing the value inside....
However both of them won't return the right values because you have to use .data() to get the data from the result:

One way

Future<bool> checkLiked(String questionID) async {
 DocumentReference ref = questionBank.doc(questionID);

 List<dynamic>? list= (await ref.get()).data()?['userLiked'];

 return list;
}

another way

Future<bool> checkLiked(String questionID) async {
 DocumentReference ref = questionBank.doc(questionID);
 List<dynamic>? list;
 await ref.get().then((value) {
  list = value.data()['userLiked'];
 });

 return list;  
}

Also

Future<bool> checkLiked(String questionID) async {
 DocumentReference ref = questionBank.doc(questionID);
 List<dynamic>? list;
 list = await ref.get().then((value) {
  return value.data()['userLiked'];
 });

 return list;  
}

And you can assign array to List<dynamic> with no casting.

user_130583710

Combining async/await and then is a recipe for problems. You should use either async/await or then, not both.

Future<bool> checkLiked(String questionID) async {
  DocumentReference ref = questionBank.doc(questionID);
  DocumentSnapshot value = await ref.get();
  List<dynamic>? list = value['userLiked'];
  print(list!.contains(uid));
  return list!.contains(uid);
}
user_2091030
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