Let's say I have a list:
d: 0w 1 2 3
I'd like to find and replace the 0w in the list. I was thinking I could index on the list to find them, returning a list of booleans, with:
d . {x=0w}
but this didn't work.
What am I doing wrong? How do I replace my 0w's with something friendlier?
If you want to find the index of each 0w you could do something like this
where 0w=d
Then if you want to replace all instances of it in d with, say 4, you can do
d[where 0w=d]:4f
Just watch out for type errors when replacing the entry
For multiple replacements you could alternatively use a dictionary:
q)d:0W 1 2 3
q)remap:0W 2!0 22
q)d^remap d
0 1 22 3
remap 0W to 0 and remap 2 to 22