Shell script to print value of variable recursively

Question

#!/bin/bash
A="X"
X="Y"
B=${$A}
echo $B # expecting output to be 'Y'

Actual output seen : line 4: ${$A}: bad substitution

user_887539 · Answer

It's called parameter indirection:

You can use ${!nameref} to treat the value of nameref as a parameter:

A="X"
X="Y"
B=${!A}
echo "$B"