Reversing of tuple containing more than 2 elements

user_17317585 0
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I'm trying to reverse a tuple in different ways. Can i change the order in way (bond,james,number). I know how to change it if there are only 2 elements in tuple but how to do it when I have 3 and more? I got (number,bond,james) but how to do it in different ways, not just reversing. My code:

def change(lst):
    list2 = [t[::-1] for t in lst]
    list2.reverse()
    return list2

print(change([("James", "Bond", "300184"),("Harry", "Prince", "111000")]))
reverse indexing list python
2 Answers

If you want to reverse the first two elements we can leverage on tuple unpacking in for loop.

lst = [("James", "Bond", "300184"),("Harry", "Prince", "111000")]
out = [(sec, fir, *rem) for fir, sec, *rem in lst]
print(out)
# [('Bond', 'James', '300184'), ('Prince', 'Harry', '111000')]

This solution would reverse each tuple in list as below:

(a, b, c...z) --> (b, a, c...z)
  • c...z can be 0 or more elements.
user_124164530

You can get all possible combinations of a tuple using itertools permutation:

from itertools import permutations
list1 = [("James", "Bond", "300184"), ("Harry", "Prince", "111000")]

for tup in list1:
    possible_permutations = permutations(tup)
    print(tuple(possible_permutations))

Output:

(('James', 'Bond', '300184'), ('James', '300184', 'Bond'), ('Bond', 'James', '300184'), ('Bond', '300184', 'James'), ('300184', 'James', 'Bond'), ('300184', 'Bond', 'James'))
(('Harry', 'Prince', '111000'), ('Harry', '111000', 'Prince'), ('Prince', 'Harry', '111000'), ('Prince', '111000', 'Harry'), ('111000', 'Harry', 'Prince'), ('111000', 'Prince', 'Harry'))
user_172905000
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