Can a non-aggregate class be a POD class C++

user_15785531 0
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From what I know if a class is not an aggregate then it is sure not a POD.

However in the following code

#include <iostream>
#include <type_traits>

class NotAggregate2
{
  int x; //x is private by default and non-static 
};

int main()
{
    std::cout << std::boolalpha;
    std::cout << std::is_pod<NotAggregate2>::value << '\n';
    std::cout << std::is_aggregate <NotAggregate2>::value << '\n';
}

which have output:

true
false

NotAggregate2 is not aggregate but a POD type.

So can a non-aggregate class be a POD class?

c++
1 Answers

Prior to C++11, you'd be correct: POD types needed to be aggregate types, which in turn could not have private non-static data members. Post-C++11 however, POD types no longer need to be aggregates. Rather, they just need to satisfy the looser requirement of being a standard layout type, which only requires that all non-static data members have the same access control, not necessarily public.

user_110821650
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