Is it possible to get the bounding box of an SVG path without placing it in the dom?
const svg = document.createElementNS("http://www.w3.org/2000/svg", "svg");
svg.setAttribute('width', '391');
svg.setAttribute('height', '391');
svg.setAttribute('viewBox', "-70.5 -70.5 391 391");
svg.innerHTML = `<rect fill="#fff" stroke="#000" x="-70" y="-70" width="390" height="390"/>
<g opacity="0.8">
<rect x="25" y="25" width="200" height="200" fill="lime" stroke-width="4" stroke="pink" />
<circle cx="125" cy="125" r="75" fill="orange" />
<polyline points="50,150 50,200 200,200 200,100" stroke="red" stroke-width="4" fill="none" />
<line x1="50" y1="50" x2="200" y2="200" stroke="blue" stroke-width="4" />
</g>`;
let box = svg.getBBox();
document.body.innerHTML += `<p>x:${box.x}, y:${box.y}, width:${box.width}, height:${box.height}</p>`;
document.body.appendChild(svg);
box = svg.getBBox();
document.body.innerHTML += `<p>x:${box.x}, y:${box.y}, width:${box.width}, height:${box.height}</p>`;
Here you can see that getBBox() returns only zeros before the image is placed. But what if I want to do something else with the image, like feeding it to a WebGL context, but I need the bounding box information? Is the most elegant method really placing the image in the dom, get the information, and then removing it?