I am wondering how to translate this Prolog code to work in Datalog.
I don't think it will work with Datalog because we are not allowed to use things like nullable(rule(z,[d])) in Datalog. Also, I do not know if Datalog allows lists. Maybe another option is to write rules as strings, but I do not know if Datalog allows strings and if all needed string functions are available.
% rules for nullable
% If we have the rule X -> Y where X does not appear in Y and each component of Y is nullable, then X is nullable
% We need that X does not appear in Y to avoid circular loops (If X is nullable it would be because of a non-circular definition so we are not omitting any case)
nullable(X) :- variable(X), rule(X,Y), \+ member(X, Y), nullable(Y). % The Y here is a list so we need to define nullable(Y) for lists which is one below
% The empty list is always a nullable list
nullable([]).
% A list is nullable if all of its components are nullable
nullable([X|Y]) :- nullable(X), nullable(Y).
% A rule X -> Y is nullable if Y is nullable
nullable(rule(_,Y)) :- nullable(Y).
Context about the code. This prolog code determines if the context-free grammar is nullable.
This means for all rules (e.g. for production S -> ABC | XYZ, the rules are: [ABC, XYZ ] ) if ANY of them is nullable then the whole rule is nullable. This is equivalent to OrLattice.
eq Rule.getNDecl().nullable() { for (int i = 0; i < getNumProd(); i++) { if (getProd(i).nullable()) return true; } return false; }This means for all terminals and non-terminals in production (e.g. for a production S -> ABC, symbols are ABC ) if ALL of them is nullable then the whole rule is nullable. This is equivalent to AndLattice.
eq Prod.nullable() { for (int i = 0; i < getNumSymbol(); i++) { if (!getSymbol(i).nullable()) return false; } return true; }an Epsilon terminal is nullable
eq Terminal.nullable() { return false; }non-terminal is nullable if its use is nullable
eq NUse.nullable(){ return decl().nullable(); }
Paper (free to download) (page 14-15)