How is this expression evaluated? "f" in "foo" == True

user_13262334 0
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>>> "f" in "foo"
True
>>> "f" in "foo" == True
False

I'm confused why the second expression is False. I see == has higher precedence than in. But then I would expect to get an exception, which is what happens when I add parentheses:

>>> "f" in ("foo" == True)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: argument of type 'bool' is not iterable

It seems the expression is only True when foo is on both sides of ==, like so:

>>> "f" in "foo" == "foo"
True
>>> "f" in "foo" == "bar"
False

What am I missing? What is Python actually calculating here?

operator-precedence python
1 Answers
user_38906320
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