How can I convert this list
(define l list '(1 2 3 4) )
to its own value 1, 2, 3 and 4
I need to do this because I have a function
(define (push! stk . args)
(stk 'push! args ) )
for this other function
((eq? msg 'push!) (set! stack (append (reverse args) stack)))
but the result I get when using push! is a list in a list, I don't want this
You can by iteration. eg. fold:
(fold cons '() '(1 2 3 4))
; ==> (4 3 2 1)
Now the most stackie functional structure is the lisp list since it is a singly linked list that constructs from end to beginning while iterates from beginning to end.
Go the other way instead - gather all the arguments in one list, and then apply:
(apply push! (cons the-stack l))