One may destructure tuple like this:
let (x,y,z) = xyz;
But is it possible to specify types for x,y, and z?
For example: xyz may be composed of f32-s but I'd like to get its components as f64-s. Unfortunately this code doesn't compile:
let (x:f64, y:f64, z:f64) = xyz;
Absolutely, you can annotate the type of the whole tuple:
let (x, y, z): (i32, &str, f32) = (10, "foo", 3.141516);
You can also partially specify them:
let (x, y, z): (i32, _, f32) = (10, "foo", 3.141516);
Note that this doesn't cast from one type to the others. In rustlang it needs to be done explicetly.