How can I print another version of the board without actually changing it?

user_17137889 0
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Suppose the

board = [[1, 0, 0], [0, 2, 0], [0, 0, 0]]

and I want to have a function that print the board in a readable version which would be like

new_board = [['X', ' ', ' '], [' ', 'O', ' '], [' ', ' ', ' ']]

This method does not change the actual board. It prints 'X' for 1, 'O' for 2, and empty space (' ') for 0.

python-3.x list python
3 Answers

You can use a translation dictionary and a nested list comprehension:

>>> symbols = {1: 'X', 2: 'O', 0: ' '}
>>> [[symbols[i] for i in row] for row in board]
[['X', ' ', ' '], [' ', 'O', ' '], [' ', ' ', ' ']]

Note that you can also use a string instead of a dictionary as @jasonharper mentioned but it will only work for this case, where keys start with 0 and are sequential:

>>> symbols = ' XO'
user_20111470

Or with map and __getitem__:

>>> symbols = ' XO'
>>> [list(map(symbols.__getitem__, x)) for x in board]
[['X', ' ', ' '], [' ', 'O', ' '], [' ', ' ', ' ']]
>>>

Or a nested map:

>>> list(map(lambda x: list(map(symbols.__getitem__, x)), board))
[['X', ' ', ' '], [' ', 'O', ' '], [' ', ' ', ' ']]
>>>

This would work for a dictionary as well:

symbols = {1: 'X', 2: 'O', 0: ' '}
user_87083640

Here is a function I made for you.

Put the board and the key in the function and It will print it for you:

board = [[1, 0, 0], [0, 2, 0], [0, 0, 0]]
key={0:" ",1:"X",2:"O"}
def printBoard(board,key,sep="|"):
  for x in board:
    for y in x:
      print(sep,key[y],end="")
    print(sep)
printBoard(board,key)

The key holds the character for each value and the sep value defines what the cells are divided by. This prints:

| X|  |  |
|  | O|  |
|  |  |  |
user_154755980
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