How to remove an item from list of maps based on specific key?

user_5540863 0
Viewed 1422

I have the following list

List<Map<String, dynamic>> filterItems = [
     {"category":1},
     {"option_val":1},
      
 ]

I also have the following map

 Map<String, dynamic> singleItem = {"category":6}

I would like to remove any item from the list above (filterItems) which has an object with key similar to singleItem map. So in my case i would like to remove the {"category":1} from the list since it has a key category similar to the map.

So i have tried the following

filterItems.remove(singleItem);
print(filterItems)

But the above doesnt work since the value of key is different so i tried the following where am now stuck on how to proceed

singleItem.map((key,value){
    filterItems.removeWhere((element) => element.containsKey(key))
})

But the above throws an error that the body of singleItem.map is returning null. How can I proceed to remove an item from the list when a key matches even though the value is different?

dart flutter
2 Answers

you can use .removeWhere as follow:

List<Map<String, dynamic>> filterItems = [
     {"category":1},
     {"option_val":1},
      
 ];
  Map<String, dynamic> singleItem = {"category":6};
  
  filterItems.removeWhere((element) => element.keys.first == singleItem.keys.first);
  print(filterItems);

and the result would be:

[{option_val: 1}]
user_108664530
  • Remove when a list has the same key
    List<Map<String, dynamic>> filterItems = [
      {"category": 1},
      {"option_val": 1},
    ];

    Map<String, dynamic> singleItem = {"category": 6};

    filterItems = filterItems.where((e) {
      return e.keys.toString() != singleItem.keys.toString();
    }).toList();
user_106494630
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