Repeated while loop with boolean

user_16884745 0
Viewed 86

Sorry if this is considered spam, yet another issue I have is that this while loop runs unconditionally and I am not sure how to fix it.

Code:

while anotherNum == True:
    playerNum = random.randint(1,10)
    total = total + playerNum
    print("")
    print("Your number is ", str(playerNum) + ".")
    print("You have " + str(total) + " in total.")
    print("")
    again = input("Roll another number? <Y or N> ")
    print("")
    if again == "Y":
      anotherNum == True
    else:
      anotherNum == False
      break
  #game finished now
print("Computer got", pcNum)
print("You got", total)
#checking for winner
while anotherNum == False:
  if (total <= 13) and (total > pcNum): 
    print("You,", name, "have won!")
  elif (pcNum <= 13) and (pcNum > total):
    print("The computer has bested you,", name + "!")
  else:
    if (total == pcNum) and (total <= 13):
      print("Draw...")
    elif (pcNum > 13) and (total <= 13):
      print("You,", name + " have won!")
    else:
      print("Both of you have lost. Wow...")

Output:

Your number is  2.
You have 2 in total.

Roll another number? <Y or N> n


Your number is  3.
You have 3 in total.

Roll another number? <Y or N> N


Your number is  3.
You have 3 in total.

Roll another number? <Y or N> N


Your number is  9.
You have 9 in total.

Instead of going to the #game finished now comment's area, the while loop repeats the process whilst only disregarding the total = total + playerNum command.

while-loop boolean python
4 Answers

You are not changing the valu

if again == "Y":
 anotherNum == True
 else:
 anotherNum == False
 break

You should use 1 equal sign as it is an assignment

if again == "Y":
 anotherNum = True
 else:
 anotherNum = False
 break
user_86225550

Your code (with minimal correction) is working just fine:

import random
total = 0
anotherNum = True

while anotherNum == True:
    playerNum = random.randint(1,10)
    total = total + playerNum
    print("")
    print("Your number is ", str(playerNum) + ".")
    print("You have " + str(total) + " in total.")
    print("")
    again = input("Roll another number? <y or n> ")
    print("")
    if again == "y":
        anotherNum = True
    else:
        anotherNum = False
        break
print("You got", total)

The output that I get after running the code:

Your number is  7.
You have 7 in total.

Roll another number? <y or n>  y


Your number is  9.
You have 16 in total.

Roll another number? <y or n>  y


Your number is  10.
You have 26 in total.

Roll another number? <y or n>  y


Your number is  2.
You have 28 in total.

Roll another number? <y or n>  y


Your number is  6.
You have 34 in total.

Roll another number? <y or n>  n

You got 34
user_160105570

Try to remove break and change == to =

import random

total = 0
anotherNum = True

while anotherNum == True:
    playerNum = random.randint(1, 10)
    total += playerNum
    print("")
    print(f"Your number is {playerNum}.")
    print(f"You have {total} in total.")
    print("")
    again = input("Roll another number? <Y or N> ")
    print("")
    if again == "Y":
        anotherNum = True  # <- HERE
    else:
        anotherNum = False  # <- HERE

OR without anotherNum variable:

import random

total = 0

while True:
    playerNum = random.randint(1, 10)
    total += playerNum
    print("")
    print(f"Your number is {playerNum}.")
    print(f"You have {total} in total.")
    print("")
    again = input("Roll another number? <Y or N> ")
    print("")
    if again == 'N':
        break
user_152399510

Here's how I would do it.

while anotherNum:
    playerNum = random.randint(1,10)
    total += playerNum
    print("")
    print("Your number is ", str(playerNum) + ".")
    print("You have " + str(total) + " in total.")
    print("")
    again = input("Roll another number? <Y or N> ")
    print("")
    anotherNum = (again == "Y")

this way you can avoid the if <blank> then true else false which caused you to make a mistake here (simple == instead of =)

user_163842990
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