I have created a simple jupyter notebook in VS Code and selected it to use my default python3 kernel (/usr/local/bin/python3). Everything works great.
Then, I close VS Code and re-open the notebook, it asks me to select the kernel every time.
Is there a way to default the kernel of this notebook to my python3 interpreter?
In case it helps, when I view the notebook json, it has the following in it:
"kernelspec": {
"name": "python3",
"display_name": "Python 3.9.6 64-bit"
It's not available for now, but they think it is a reasonable request, and considering it. You can refer to this page.
Two ways
one:
You can go into the command Juptyer: Filter Kernels
use command to filter out kernals, all kernals follow alphanumeric order. So, u can tick a few https://github.com/microsoft/vscode-jupyter/discussions/10130
two:
ps. Can try, but might not work after a while? idk why, but it works once.
Enforce choices to only 1, then reload vscode windows
"jupyter.kernels.filter": [
{
"path": "/bin/python3"
}
]
Meanwhile you can visually browser all the paths on ur local Click the text button at the top right corner. <Python 3.x****>
It pops up like below
