jQuery to delete hide table row if based on contents of two cells within row

Question

I'm trying to write a script for tampermonkey that hides a row in a table based on two conditions.

Condition 1: The cell in column 3 doesn't contain '/'

Condition 2: the cell in column 3 does contain '0:0'

I've got condition 1 working on its own with the following jQuery

$("td:nth-of-type(3):not(:contains('/'))").parent ().hide ();

and condition 2 with

$("td:nth-of-type(3):contains('0:0')").parent ().hide ();

but I haven't been able to combine them, I've tried the following:

$("[td:nth-of-type(3):contains('0:0')][td:nth-of-type(3):not(:contains('/'))]").parent ().hide ();

but no luck. How can I combine the conditions? I've tried to include an if statement but haven't been able to get that working either.

user_7644018 · Answer

You were heading in the right direction. Keep chaining the :contains and :not(:contains(...)) calls.

Try the runnable example below, note that the 1st and 4th rows are hidden.

$("td:nth-of-type(3):contains('0:0'):not(:contains('/'))").parent().hide();