Class object mistaken as an int

user_16570000 0
Viewed 46

I am making a tree class to practice, and I have arrived at this.

class Node():
def __init__(self,val):
    self.val = val
    self.right = None
    self.left = None
    self.count = 1
def add(self,node):
    if self.val > node.val:
        if self.left == None:
            self.left = node
        else:
            self.left.add(node)
    elif self.val < node.val:
        if self.right == None:
            self.right = node
        else:
            self.right.add(node)
    else:
        self.count +=1
def count(self):
    if self.right and self.left:
        self.right.count()
        self.left.count()
    elif self.right:
        print(self.value)
        self.right.count()
    elif self.left:
        print(self.value)
        self.left.count()
    else:
        pass

But, when calling it, I have a problem.

a = Node('a')
>>> a.add(Node('a'))
>>> a.add(Node('b'))
>>> a.count()
Traceback (most recent call last):
  File "<pyshell#73>", line 1, in <module>
    a.count()
TypeError: 'int' object is not callable
>>> 

>>> type(a.right)
<class '__main__.Node'>

How can I fix this? Through debugging, it seems the problem is at self.right.count() function. Also, I am on Python 3.9.4.

python-3.x class python
2 Answers

You have an int field and method count. Rename one of them and problem will be solved. Also you have

print(self.value)

line, but your field name is val.

user_157773700

The integer referred to in the error is a.count. The problem is that count is used in two ways by the class: (1) as a method name, and (2) as an instance attribute name.

When an instance of Node is created, the __init__ method creates an instance attribute count in the following:

    self.count = 1

This masks the method of the same name. So when you do a.count(), it's using 1 for a.count.

To fix it, just use different names for method vs. the instance attribute.

user_54607190
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