number to string conversion with padding in awk

user_15026979 0
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I am trying to convert a number to a string in awk. I would like my string to be left-padded with zeros. E.g., 3 would become "00000003". I have the following test case:

gawk 'BEGIN { CONVFMT = "%08d" ; a = 233 ; print ""a }'

233

It prints "233" not "00000233". Replacing a = 233 with a = 233.0 doesn't change anything. However, replacing a = 233 with a = 233.1 changes everything, and my one-liner correctly prints padded string:

gawk 'BEGIN { CONVFMT = "%08d" ; a = 233.1 ; print ""a }'

00000233

What am I missing ???

awk
1 Answers

CONVFMT is not used here. In the gawk manual it says:

As a special case, if a number is an integer, then the result of converting it to a string is always an integer, no matter what the value of CONVFMT may be. Given the following code:

   CONVFMT = "%2.2f"
   a = 12
   b = a ""

b has the value "12", not "12.00".

It wouldn't print 00000233 even if 233.0 was used:

$ gawk 'BEGIN { CONVFMT = "%08d"  ; a = 233.0 ; print ""a }'
233

You should use sprintf to achieve what you want:

$ gawk 'BEGIN { a=233; name=sprintf("%08d",a); print name }'
00000233
user_36918910
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