python code to reverse an array without using the function

user_16445347 0
Viewed 636

My task is to create an empty array and take the input from the user, but I have to print the input element in a reversed order without the function, that too in an array itself.

x=int(input('how many cars do you have'))
a=[]
for i in range(x):
    car=(input('enter your car name'))
    a.append(car)
    
    print(a)
y=[]
for i in range(length(a)-1,-1,-1):
    y.append(a[i])
    
    print (y)

Why am i getting repeated reverse array output with this code. Can anyone please tell me what's wrong in this

reverse arrays python
6 Answers

Use slicing on any sequence to reverse it :

print(list[::-1])
user_162582420

If your looking for a method from scratch without using any built-in function this one would do

arr = [1,2,3,5,6,8]
for i in range(len(arr)-1):
  arr.append(arr[-2-i])
  del(arr[-3-i])
print(arr)
# [8, 6, 5, 3, 2, 1]
user_111857660

Do you want to reverse your list?

a = ['car1', 'car2', 'car3']
a.reverse()
print(a)

['car3', 'car2', 'car1']
user_152399510

you should use slicing. for example,

a = ['1','2','3']
print(a[::-1])

will print ['3','2','1']. I hope this will work for you.

Happy Learning!

user_118672990

enter image description hereYour code is giving me the correct output except that len() is used to calculate the length of a list and not length().

x=int(input('how many cars do you have')) 
a=[] 
for i in range(x): 
    car=(input('enter your car name')) 
    a.append(car)
print(a)
y=[] 
for i in range(len(a)-1,-1,-1): 
    y.append(a[i])
print(y)
user_140742470

Simple Custom way (without using built-in functions) to reverse a list:

def rev_list(mylist):
    max_index = len(mylist) - 1
    return [ mylist[max_index - index] for index in range(len(mylist)) ]
rev_list([1,2,3,4,5])

#Outputs: [5,4,3,2,1]
user_132479310
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