I am new to the shell script, I have a text file with multiple records, and the 1st record end and second record start in the same line as below
"-}{"
So I want to break the chain as
"-} #line1
{ #line2"
I tried like below: Method 1
sed 's/\-\}\{//\-\} \n \{' file.txt
Method 2
tr '-}{' '\n'
Can anyone please help me with this?
Too much escaping.
Also it's s/<pattern>/<replacement>/. There are 3 /, the last one on the end.
$ echo '"-}{"' | sed 's/-}{/-} \n {/'
"-}
{"
It's not possible to with tr, tr is for single character translate. If you would like tr -- '-}{' '\n' then tr would replace any of -, } and { by a newline.
With your shown samples, please try following awk code. Simply substituting -}{ with -} new line { and printing the value.
echo '"-}{"' | awk '{sub(/-}{/,"-}\n{")} 1'
This might work for you (GNU sed):
sed 'G;:a;s/-}\({.*\(.\)\)/-}\2\1/;ta;s/.$//' file
Append a newline to the current line.
Use pattern matching to insert the newline between -} and { repeatedly.
When all is done, remove the introduced newline.
You can use () to capture the delimiters and do this:
echo '"-}{" -} -}{' | sed -E 's/(-})({)/\1\n\2/g'
"-}
{" -} -}
{