kotlin, unit test how to assert a class constructor is not public

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converting java to kotlin, it has a java package level visibility class

class NotificationManager extends Base {

    NotificationManager(Context context) {
        super(context);
        ... ...
    }

the unit test to assert this constructor is not public

    @Test
    public void verify_Constructor() throws NoSuchMethodException, IllegalAccessException, InvocationTargetException, InstantiationException {
        Constructor<NotificationManager> constructor = NotificationManager.class.getDeclaredConstructor(Context.class);
        constructor.newInstance(application);
        assertFalse(Modifier.isPublic(constructor.getModifiers()));
    }

after convert kotlin, it is turned into internal visibility

internal class NotificationManager internal constructor(context: Context) : Base(context) {...}

but the test failed at assertFalse(Modifier.isPublic(constructor.getModifiers()));.

In unit test how to assert a kotlin internal class constructor is not public?

kotlin unit-testing constructor
1 Answers

You can use Kotlin reflection to get the KVisibility of the constructor and check that.

@Test
public void verify_Constructor() {
    KClass<?> kClass = JvmClassMappingKt.getKotlinClass(NotificationManager.class);
    boolean hasPublicConstructor = kClass.getConstructors().stream()
            .map(KFunction::getVisibility)
            .filter(Objects::nonNull) // package-private and java-protected are null
            .anyMatch(kVisibility -> kVisibility.equals(KVisibility.PUBLIC));
    assertFalse(hasPublicConstructor);
}
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