Hot to replace the stdout the last line of the last control character via sed command?

user_9725400 0
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I wanna replace(delete) the last line of the last control character newline form ls command stdout result. Which I had try sed command is :

ls | sed '$ s/[[:cntrl:]]$//'
ls | sed '$ s/[[:graph:]]$//'
ls | sed '$ s/[[:print:]]$//'

The result I want like this result ls | head -c -1

Any wrong with my sed command? Thanks !

regexp-replace sed bash
2 Answers

sed appears to automatically add a newline if the current line was terminated with a newline, and I don't see how to turn that behaviour off.

You might try a different approach: capture the output of the command (the command substitution syntax strips trailing newlines); and then print it without a newline

printf '%s' "$(ls)"
user_75520

This might work for you (GNU sed):

sed -z 's/\n$//' file
user_9674920
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