Admin
1
sample list [1, 0, 0, 1, 0, 0, 1, 0, 0, 0]
1 means occupied and 0 means unoccupied
expected output: occupied [0,3,6] unoccupied: [1,2,3,4,5,6,7,9]
def row_seats(seats):
occupied_seats =[]
vacant_seats =[]
for x in seats:
if x == 0:
vacant_seat.index(x)
elif x == 1 :
occupied_seats.index(x)
this is what i have done so far but i do not think i am approaching it properly any help would be appreciated!
You need to use enumerate to access the correct index,
def row_seats(seats):
occupied_seats =[]
vacant_seats =[]
for ind, x in enumerate(seats):
if x == 0:
vacant_seats.append(ind)
elif x == 1 :
occupied_seats.append(ind)
return vacant_seats, occupied_seats
seat_list = [1, 0, 0, 1, 0, 0, 1, 0, 0, 0]
vacant, occupied = row_seats(seat_list)
print(vacant)
print(occupied)
The original vacant_seat.index(x) was wrong because it was trying to search for x in an empty list. The correct approach appends the index to the respective lists.
Using index was also incorrect. Even if used properly (on the original - input list, with appending), you were obtaining an index of either 0 or 1. This would persistently return the index of only the first occurrence of those values.
