How to POST multipart/form-data in Python with requests

user_12908346 0
Viewed 6824

Currently working on a project and I need to post this request:

curl -X POST "http://localhost:8000/api/v1/recognition/recognize" \
-H "Content-Type: multipart/form-data" \
-H "x-api-key: xxxxxx-xxxxx-xxxx-xxxx-xxxxxxxx" \
-F "file=@<image>.jpg"  #image

Tried several times with this code snippet had no luck:

import requests
headers = {
    'Content-Type': 'multipart/form-data',
    'x-api-key': 'xxxxxxxxxxxx',
}
files = {
    'file': ('image.jpg', open('image.jpg', 'rb')),
}
response = requests.post('http://localhost:8000/api/v1/recognition/recognize', headers=headers, files=files)
print(response)

Am I doing something wrong or missing something?

python-requests python
3 Answers

I made it work with this code:

import requests
url = "http://10.0.38.119:8000/api/v1/recognition/recognize"
payload = {}
files = [('file', ('<image>.jpg', open('<image>.jpg', 'rb'), 'image/jpeg'))]
headers = {
  'x-api-key': 'xxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxx'
}
response = requests.request("POST", url, headers=headers, data=payload, files=files)
print(response.text)
user_129083460

try with this

import requests

headers = {
    'Content-Type': 'multipart/form-data',
    'x-api-key': 'xxxxxx-xxxxx-xxxx-xxxx-xxxxxxxx',
}

files = {
    'file': ('<image>.jpg', open('<image>.jpg', 'rb')),
}

response = requests.post('http://localhost:8000/api/v1/recognition/recognize', headers=headers, files=files)
user_40466320

The -H flag means that you're passing a header, not a file.

>>> import requests
>>> 
>>> headers = {
...     "Content-Type": "multipart/form-data",
...     "x-api-key": "xxxxxx-xxxxx-xxxx-xxxx-xxxxxxxx"
... }
>>> 
>>> file = {"file": ("<image>.jpg", open("<image>.jpg", "rb"))}
>>> 
>>> r = requests.post("http://localhost:8000/api/v1/recognition/recognize",
...     headers=headers, files=file
... )
user_131310470
Related