Make certain part of string bold using preg_replace()

user_5970123 0
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I have a string of a comment that looks like this:

**@First Last** rest of comment info.

What I need to do is replace the ** with <b> and </b> so that the name is bold.

I currently have this:

$result = preg_replace('/\*\*/i', '<b>$0</b>', $comment);

But that results in:

"<b>**</b>@First Last<b>**</b> rest of comment info"

Which is obviously not what I need. Does anyone have any suggestions on how to achieve this?

php
1 Answers

A better idea would be to use a markdown parser library which does this for you.
Improper use of the regular expressions can lead to security vulnerabilities with unclosed tags etc..
However, a simple approach could be this:

$result = preg_replace('/\*\*(.+)\*\*/sU', '<b>$1</b>', $comment);

The U means ungreedy and takes the first possible match.
The s modifies . to be any character, including newline.
(see modifiers page)

This also works with an example text like this:

**@First Last** rest of comment info **also bold**.
The next line also **has a bold example**. This spans **two
lines**.

I am sure there are counter examples which are broken with this. Again, please use a proper markdown library to do this for you (or copy their implementation if the LICENSE allows it).

user_104416710
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