I implemented binary search in two ways and wondering which is more efficient? please help me know which is more efficient and how can it further be optimized? is time complexity remains same in both approach? I am a beginner in programming.
approach 1;
#include<iostream>
using namespace std;
bool BinarySearch(int*a,int n,int s ){
if(n==1){
if(a[0]==s)
return true;
else
return false;
}
else{
if(s<a[n/2]){
int U[n/2];
for(int i=0;i<n/2;i++){
U[i]=a[i];
}
return BinarySearch(U,n/2,s);
}
else{
int V[n-n/2];
for(int i=0;i<n-n/2;i++){
V[i]=a[i+n/2];
}
return BinarySearch(V,n-n/2,s);
}
}
}
int main(){
int array[10]={2,4,6,8,10,12,14,16,18,22};
cout<<BinarySearch(array,10,9);
}
approach 2:
#include<iostream>
using namespace std;
bool Bsearch(int arr[],int s,int l,int x){
cout<<"calling bsearch with arguments "<<s<<' '<<l<<' '<<x<<endl;
if(l==1)
return arr[s]==x;
int h=l/2;
if(x<arr[s+h])
return Bsearch(arr,s,h,x);
else
return Bsearch(arr,s+h,l-h,x);
}
int main(){
int marks[11]={17,18,20,22,24,26,28,30,32,34,36};
cout<<Bsearch(marks,0,11,32);
}
Thanks in advance for the kind help.