bash directly executes overflown characters

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I encountered something weird while trying C read function. I know file descriptor 0 means standard input. So I decided to take input with read function like below

 #include<unistd.h>
 int main(){
   char buf[1];
   read(0,buf,1);
   return 0;
 }

I compiled that main.c file with gcc

$ gcc -o main main.c

then I executed main binary and then entered input 'tls'. Characters after 't' are interpreted by the shell and output was like the following

$ ./main
  tls
$ ls
  main main.c

Why the shell directly interprets overflown input characters?

file-descriptor c bash
1 Answers

Nothing is overflowed. Your program reads one character from stdin and then exits. Any characters after that are read by the shell.

user_1529480
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