Python list reversed can't be accessed more than once

reversed returns an iterator. When you first call list on it, you iterated on it till the end and it has nothing to give back anymore. So if you call list again, it immediately says "stop iteration" and you get an empty list.

Fix is to store it when you first call list on it:

>>> arr = list(reversed(np.arange(11)))
>>> arr
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]

Though, in numpy's context you wouldn't cast to list but reverse in numpy domain:

>>> arr = np.arange(11)[::-1]

or

>>> arr = np.arange(10, -1, -1)

or

>>> arr = np.flip(np.arange(11))

or

>>> arr = np.flipud(np.arange(11))

to get

>>> arr
array([10,  9,  8,  7,  6,  5,  4,  3,  2,  1,  0])

The reversed method

Return a reverse iterator over the values of the given sequence

Once the iterator is consumed, it's empty

If you consume it and store in a list, then you can use it multiple times

import numpy as np

arr = list(reversed(np.arange(11)))
print(list(arr))  # [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
print(list(arr))  # [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
print(list(arr))  # [10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]

This has to do with the return of reversed(). You anticipate that it is a list, but it is an iterator

import numpy as np

arr = reversed(np.arange(11))

>>> print(list(arr))
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
>>> print(list(arr))
[]
>>> print(list(arr))
[]

After the firt run, the iterator is empty. You can prevent this by creating a list from the iterator and then print it:

arr2 = list(reversed(np.arange(11)))
>>> print(list(arr2))
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
>>> print(list(arr2))
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
>>> print(list(arr2))
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]