I have two python lists in following form:
A = [(1,''), (1, 'ABC'),(1,''), (1, 'DEF'),(1,''), (1, 'GHI'),(1,''), (1, 'LMO'),(1,'')]
B = ['ABC', 'ghi', 'PQR']
(Note: A is a list of list. B is normal list.)
I want to create a pandas DF that will only contain element that are common from both the lists and the form will be:
DF :
A B
ABC ABC
GHI ghi
Please note there might be lower case- upper case and also white spaces
Try:
t = [v for _, v in A if v in B]
df = pd.DataFrame({"A": t, "B": t})
print(df)
Prints:
A B
0 ABC ABC
1 GHI GHI
To handle upper/lower cases:
B = [v.upper() for v in B]
t = [v.upper() for _, v in A if v.upper() in B]
df = pd.DataFrame({"A": t, "B": t})
print(df)
you can try:
import numpy as np
a = np.intersect1d(np.array(A)[:,1], np.array(B))
df = pd.DataFrame({'A': a, 'B': a})
Input data:
>>> dfA
_ A
0 1
1 1 AbC
2 1
3 1 DEF
4 1
5 1 G H I
6 1
7 1 LMO
8 1
>>> dfB
B
0 ABC
1 GHI
2 PQR
>>> pd.merge(dfA, dfB,
left_on=dfA["A"].str.upper().str.replace(' ', ''),
right_on=dfB["B"].str.upper().str.replace(' ', ''))[["A", "B"]]
A B
0 AbC ABC
1 G H I GHI
import pandas as pd
A = [(1,''), (1, 'ABC'),(1,''), (1, 'DEF'),(1,''), (1, 'GHI'),(1,''), (1, 'LMO'),(1,'')]
B = ['ABC', 'GHI', 'PQR']
A = [i[1] for i in A if i[1] in B]
df = pd.DataFrame({'A':A,'B':A})
print(df)
to take care about case sensitivity and spaces try this:
import pandas as pd
A = [(1,''), (1, 'ABC'),(1,''), (1, 'DEF'),(1,''), (1, 'GHI'),(1,''), (1, 'LMO'),(1,'')]
B = ['ABC', 'GHI', 'PQR']
A = [i[1] for i in A if i[1].lower().replace(' ', '') in [x.lower().replace(' ','') for x in B]]
df = pd.DataFrame({'A': A, 'B': A})
print(df)
Try:
t = [v for _, v in A if v in B]
df = pd.DataFrame({"A": t, "B": t})
print(df)
Prints:
A B
0 ABC ABC
1 GHI GHI
To handle upper/lower cases:
t = [v.upper() or v.lower() for _, v in A if v.upper() or or v.lower() in B]
df = pd.DataFrame({"A": t, "B": t})
print(df)